2x^2+4x+5=x(2x-1)

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Solution for 2x^2+4x+5=x(2x-1) equation:


Simplifying
2x2 + 4x + 5 = x(2x + -1)

Reorder the terms:
5 + 4x + 2x2 = x(2x + -1)

Reorder the terms:
5 + 4x + 2x2 = x(-1 + 2x)
5 + 4x + 2x2 = (-1 * x + 2x * x)
5 + 4x + 2x2 = (-1x + 2x2)

Add '-2x2' to each side of the equation.
5 + 4x + 2x2 + -2x2 = -1x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
5 + 4x + 0 = -1x + 2x2 + -2x2
5 + 4x = -1x + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
5 + 4x = -1x + 0
5 + 4x = -1x

Solving
5 + 4x = -1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add 'x' to each side of the equation.
5 + 4x + x = -1x + x

Combine like terms: 4x + x = 5x
5 + 5x = -1x + x

Combine like terms: -1x + x = 0
5 + 5x = 0

Add '-5' to each side of the equation.
5 + -5 + 5x = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 5x = 0 + -5
5x = 0 + -5

Combine like terms: 0 + -5 = -5
5x = -5

Divide each side by '5'.
x = -1

Simplifying
x = -1

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